"6 snow white boomers."
Apparently, a famous song.
I'm still not really doing much. But I'm sure I'll manage.
Differentiate:
X . sqrt(X+1)
Can't seem to find the path to the solution given.
Hoping I get some help.
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6 comments:
You differentiate it as a product using the product rule.
u = x
u' = 1
v = (x+1)^(1/2)
v' = 1/[2(x+1)^2]
dy/dx = uv' + vu'
= x/2(x+1)^2 + (x+1)^1/2
i hope this isnt something ive missed this year
I dozed off during differentiation because curve sketching was more fun. I'm screwed for 11&12, aren't I?
NO NOT SCREWED FOR YEAR 11 12 BECAUSE YEAR 11 12 IS NEXT YEAR GUYS HEAR ME NEXT YEAR NEXT YEAR
I'm still halfway through doing logarithms. Need more maths.
i feel slightly confused. because i got (x+2)/[2(x+1)^(3/2)] which is the same as (x+2)/[2(x+1)(x+1)^(1/2)].
and jm, you can use the quotient rule. and for the product rule, v is meant to be (x+1)^(-1/2).
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